When bonded, the hydrogen atom

When bonded, the hydrogen atoms have their electron taken byOxygen atom, which gives them a partial positive charge of E. Theoxygen, therefore, has a net negative charge of -2e. The distancebetween oxygen and hydrogen is 0.9584 Angstrom. FIND the net forceon the oxygen atom. ( please explain them in details with giveninformation )

Answer:

The force extered on the oxygen atom by each hydrogen atom, fromCoulomb’s law, is given by :

F = ( 1 / 4o) ( e x 2e ) / d2, in magnitude,

where, e = 1.6 x 10-19 C is the electroniccharge,

d = 0.9584 Angstrom = 9.584 x 10-11 m is the distancebetween two atoms,

and, ( 1 / 4o) = 9 x 109 S.I. is permittivity constant.

Hence, F = (  9 x 109 ) x 2 x ( 1.6 x10-19 / 9.584 x 10-11 )2 N ~ 5 x10-8 N.

We know, there is an 105o angle between the H – O – Hbond in a water molecule.

Hence, net force on the oxygen atom is :

( F2 + F2 + 2F2 cos105o )

= 2 x F x ( 1 + cos 105o )

= 2 x 5 x 10-8 x ( 1 + cos 105o ) N

~ 6.087 x 10-8 N.


 
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