The number x of bottles of gar
Answer:
Solution :
a) Sum of all probabilities must be equal to one. Hence,
0.135 + 0.141 + 0.150 + p + 0.134 + 0.122 + 0.101 + 0.074 =1
0.857 + p = 1
p = 1 – 0.857
p = 0.143
b) We have to find P(X ≤ 2).
P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)
P(X ≤ 2) = 0.135 + 0.141 + 0.150
P(X ≤ 2) = 0.426
Hence, the probability that at most two bottles will besold on a randomly selected day is 0.426.
c) We have to find P(X ≥ 2).
P(X ≥ 2) = 1 – P(X < 2)
P(X ≥ 2) = 1 – [P(X = 0) + P(X = 1)]
P(X ≥ 2) = 1 – [0.135 + 0.141]
P(X ≥ 2) = 1 – 0.276
P(X ≥ 2) = 0.724
Hence, the probability that at least two bottles will besold on a randomly selected day is 0.724.
d) The average for a discrete random variable is given by,
The average number of bottles sold per day is3.14.
e) The standard deviation is given as follows :
We have, E(X) = 3.14
Now,
The standard deviation of the number of bottles sold perday is 2.1504.
Please rate the answer. Thank you.
"Our Prices Start at $11.99. As Our First Client, Use Coupon Code GET15 to claim 15% Discount This Month!!"
![](https://writinghelpe.com/wp-content/uploads/2022/08/save.jpg)