For each of the following (rea
For each of the following (real or imaginary) complexesdetermine a0 the number of electrons in the coordination sphere andb0 the oxidation state of the metal in each of the complexes.
a. (CO)5Cr=C(OEt)Me
b.NbBr3(PPh3)2(=CHCMe3)
c. (Me3CO)3W(triple bondCCMe3)
d.[(n5-C5H5)RuCl(Me)(PMe3)]–
e.[(n5-C5H5)Ir(PMe3)(=CH2)]+
Answer:
(a) (CO)5Cr=C(OEt)Me
Electron inside the coordination sphere count
5 CO = 10 e, Cr = 6e, =C = 2e, Total electron 18, and oxidationstate +2
(b)NbBr3(PPh3)2(=CHCMe3)
Electron count inside coordination sphere: Nb = 5e, 3Br = 3,2PPh3 = 4e, =C = 2 ; Total electron count = 14 e,Oxidation state of Nb is +5.
(c) (Me3CO)3W(triplebondCCMe3)
Electron count inside coordination sphere: 3e from 3(Me3CO), 6efrom W, and 3e from triple bondCCMe3 . Total electroncount =12 e; Oxidation state of metal ion is +6.
(d) [(n5-C5H5)RuCl(Me)(PMe3)]–
Electron count inside coordination sphere: 5e from(n5-C5H5), 8e from Ru, 1e from Cl,1e from Me, 2e from PMe3 ; Total electron count =17+1(from negative charge) =18 e; Oxidation state of metal ion is+2.
e.[(n5-C5H5)Ir(PMe3)(=CH2)]+
Electron count inside coordination sphere: 5 e from(n5-C5H5), 9e from Ir, 2e fromPMe3, 2e from (=CH2 ). Total electron count =18-1(positive charge) =17 , Oxidation state of metal ion is +4.
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