# determines the specific heat o

determines the specific heat of the iron if 50 g of cloves are placed in 100 ml of cold water at 10º C and 100 ml of hot water at 70º C are added.The temperature of the mixture is 35.5ºC

1 L = 1000 g 1 mL = 1 g 100 mL = 100 g = m ( mass of water )

Mass of iron = M = 50 g

Specific heat of water = cw = 4.2 J / goC

Final temperature of the mixture = T = 35.5o C

Let, the specific heat of iron be CI in J / goC and initial temperature of iron be t

Hence, according to principle of calorimetry,

Heat gained by ( iron + water ) at 10 C = Heat gained by waterat 70o C

M x CI x ( T – t ) + m x cw x ( T – 10 ) = mx cw x ( 70 – T )

50 x CI x ( 35.5 – t ) + 100 x 4.2 x ( 35.5 – 10 ) = 100x 4.2 x ( 70-35.5 )

50 ( 35.5 – t ) CI + 10710 = 14490

50 ( 35.5 – t ) CI = 14490 – 10710 = 3780

( 35.5 – t ) CI = ( 3780 / 50 ) = 75.6

Specific heat of iron = CI = 75.6 / ( 35.5 – t ),where, t = initial temperature of iron.

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