calculate the reactions conver
calculate the reactions conversion percent (by hand and solverin excel) to be able to find good result in aspen in producingEthylene oxide. The given reactions are:
C2H4+ 0.5O2 –> C2H4O
C2H4+ 3O2 –> 2CO2+2H2O
C2H4O + 2.5O2 –> 2CO2+2H2O
Along with stream data (COMPONENT FLOWRATES (Kmol/h) related tofirst and second reactors as followed:
First reactor input
Ethylene –>1047.91
Ethylene oxide –> 6.47
Carbon dioxide–> 31.71
Oxygen –> 6331.12
Nitrogen –> 28,191.39
Water –> 30.98
First reactor output:
Ethylene –> 838.67
Ethylene oxide –> 206.79
Carbon dioxide –> 49.56
Oxygen –> 6204.19
Nitrogen –> 28,191.39
Water –> 48.82
Second reactor output:
Ethylene –>670.64
Ethylene oxide –> 175.83
Carbon dioxide –> 63.44
Oxygen –> 6101.72
Nitrogen –> 28,188.72
Water –> 77.13
Answer:
% Conversion for any reactant is defined as = kmole reacted /kmole of feed. The below table indicates the kmol distribution ofreactants and products from reactor 1 & 2.
|
Compo nent |
Ist reactor Inlet ; N1 (kmol/hr) |
Mole reacted/generated = Reactor inlet – Reactor outlet = N1-N2 |
Ist reactor Outlet OR 2nd Reactor Inlet ; N2 (kmol/hr) |
Mole reacted/generated = Reactor inlet – Reactor outlet = N2-N3 |
2nd reactor Outlet; N3 (kmol/hr) |
|
C2H4 |
1047.91 |
209.24 |
838.67 |
168.03 |
670.64 |
|
C2H4O |
6.47 |
-200.32 |
206.79 |
30.96 |
175.83 |
|
CO2 |
31.71 |
-17.85 |
49.56 |
-13.88 |
63.44 |
|
O2 |
6331.12 |
126.93 |
6204.19 |
102.47 |
6101.72 |
|
N2 |
28191.39 |
0 |
28191.39 |
2.67 |
28188.72 |
|
H2O |
30.98 |
-17.84 |
48.82 |
-28.31 |
77.13 |
Note : + ve sign indicatesreactant being consumed in the reaction; – ve sign indicatesproduct being formed in the reactor
| Firstreactor | ||
|
% Conversion with respect to C2H4 = 209.24 * 100 /1047.91 = 19.9 % |
||
|
% Convsersion with respect to C2H4O is not feasible in firstreactor as C2H4O product, is formed in the reaction. |
||
| Secondreactor | ||
% Conversion with respect toC2H4 =
|
||
| % Convsersion with respect toC2H4O = | ||
|
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