# Calculate the delta G’naught.

Calculate the delta G’naught.

Malate + pyruvate –> oxaloacetate + lactate

Oxaloacetate + (2H+) + (2e-) –> malate E’naught= -0.166

Pyruvate + (2H+) + (2e-) –> lactate E’naught = -0.185

Not sure how to calculate the delta G’naught. Both are recievingelectrons. But my guess is that the reduction of malate is morefavorable becaue of a higher E’naught. Therefore the overallreaction, guessing, would tend toward the left.

Oxaloacetate + (2H+) + (2e-) –> malate   E0= -0.166V

Pyruvate + (2H+) + (2e-) –>lactate      E0 = -0.185V

malate ——————-> Oxaloacetate + (2H+) +(2e-)       E0 =0.166v

Pyruvate + (2H+) + (2e-) ——-> lactate   E0 = -0.185V

——————————————————————————————-‘

Malate + pyruvate –> oxaloacetate +lactate                            E0 Cell = -0.019V

n= 2

G0  = -nE0cell*F

= -2*-0.019*96500

= 3667J    = 3.667KJ

G0> 0 it non spontaneous reaction.

The overall reaction to wards revers(left side)

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