A tug of war has teachers and
A tug of war has teachers and the principal challenging thestudents! In the first round 3 teachers and 5 students came to adraw. In the second round the principal joined the students. Theprincipal and 10 students came to a draw against 8 teachers in thesecond round. Assuming each teacher has the same strength, and eachstudent has the same strength, who will win the tie breaking roundif it is: 15 students and the principal challenging 10 teachers?Show your thinking.
Answer:
In the first round 3 teachers and 5 students came to a draw.Hence, the strength of a student is 3/5th of thestrength of a teacher.
In the second round, the principal and 10 students came to adraw against 8 teachers. The strength of 10 students is equal tothe strength of (3/5)*10 = 6 teachers . Hence, the strengths of 6teachers and the principal is equal to the strength of 8 teachersso that the strength of the principal is equal to the strength of 2teachers.
Now, in the tie breaking round, 15 students and the principalare challenging 10 teachers. The strength of 15 students equals thestrength of (3/5)*15 = 9 teachers and the strength of the principalis equal to the strength of 2 teachers. Therefore, the strengths of15 students and the principal is equal to the strength of 11teachers. Since they are challenging 10 teachers, hence, 15students and the principal will win the tug of war.
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