# A poll of 2,160 randomly selec

A poll of 2,160 randomly selected adults showed that 92​% ofthem own cell phones. The technology display below results from atest of the claim that 91​% of adults own cell phones. Use thenormal distribution as an approximation to the binomial​distribution, and assume a 0.01 significance level to completeparts​ (a) through​ (e). Test of p=0.91 vs p≠0.91

Sample=1 x=1,981 n=2,160 sample p= .917130 95%CI=​(0.901850,0.932409) z-value=1.16 p-value= .247

Null hypothesis

Alternative hypothesis

We have for given example,             Population proportion value is =0.91         x=1981                       n=2160          Level of significance =   0.01         Estimate for sample proportion = 0.917130                  Z test statistic formula for proportion      P-value   =0.247 ………………………by usingExcel command =2*(1-NORMSDIST(1.16)) or by using Z table.  Decision:Do not reject   H0

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