1A) The lengths of pregnancies
1A) The lengths of pregnancies in a small rural village arenormally distributed with a mean of 266 days and a standarddeviation of 15 days.In what range would you expect to find the middle 50% of mostpregnancies?Between and .1B) If you were to draw samples of size 30 from this population, inwhat range would you expect to find the middle 50% of most averagesfor the lengths of pregnancies in the sample?Between and .
Answer:
Solution:
1A)
Middle 50% as the to z values are -0.674 and 0.674
Using z-score formula,
x = z * 
+ 
x = -0.674 * 15 + 266 = 255.89
and
x = 0.674 * 15 + 266 = 276.11
Between 255.89 and 276.11
1B)
= / 
n = 15 / 30 = 2.7386
Middle 50% as the to z values are -0.674 and 0.674
Using z-score formula,
= z * + 
= -0.674 * 2.7386 + 266 = 264.15
and
= 0.674 * 2.7386 + 266 = 267.85
Between 264.15 and 267.85
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