1. Given the following data, t
1. Given the following data, test at the 0.05 level ofsignificance to see if the number of dogs treated at two differentvet clients differs. Assume variances are equal.Clinic A (doges treated per 10 randomly selected day); 10, 11, 15,4, 8, 9, 14, 5, 18, 20 Clinic B (dogs treated per 7 randomlyselected day): 11, 16, 15, 18, 14, 16, 182. Given the following data, test to see if the company with newertechnology has greater output than the company with oldertechnology. Test at the 0.05 level of significance and do notassume equal variances.Company A (with new technology): 1123, 1120, 1000, 1500,1500,Company B (with old technology): 1000, 990, 890, 930, 870Test for Two Variances3. For both SPSS problems 1 & 2 above, use the Levene’s F-valueprovided in the output to test to see if variances are equalbetween the two groups being evaluated.
Answer:
The data is added into SPSS as follows:
The test is run from Analyse -> Compare Means ->Independent two sample tests. The grouping variable is the VAR 002in our data. The output of SPSS is as follows:
Assuming variances are equal, t – -1.865 and p= 0.082. Hence, wecannot reject the null hypothesis and can conclude that the meannumber of dogs treated at two different vet clients do notdiffer.
3. a) From Levene’s test,
Null Hypothesis: The population variances are equal
F-value = 4.628 and p= 0.048
As the p-value<0.05, we can reject the null hypothesis andsay that the population variances are not similar for both thegroups.
2. We will run the test similarly as in Question 1. The outputof the SPSS is:
Assuming variances are not equal,
t = 2.890, We will compute the one-tailed p-value which is0.019. As the p-value<0.05, we can reject the null hypothesis.We can say that the newer technology has greater output then theolder technology.
3. b) From Levene’s test,
F = 22.941, p = 0.001
As the p-value<0.05, we can reject the null hypothesis.Hence, we can say that the variances of both the population groupsare not similar.
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